Computer C++ program to find the LCM and GCD of two numbers 2012
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#include
#include
void main()
{
clrscr();
int x,y,gcd=1;
cout<>x;
cout<>y;
for(int i=1;i<1000;++i)
{
if((x%i==0)&&(y%i==0))
gcd=i;
}
cout<<"\n\n\nGCD :"<
cout<<"\n\n\nLCM :"<<(x*y)/gcd;
getch();
}
OUTPUT:
ENTER 1st NO : 12
ENTER 2nd NO. :13
GCD :1
LCM :156
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Explain Relative addressing mode and Base Register addressing Mode
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Error: Your comment is too short. Please try to explain your query.
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Computer C++ program to find the LCM of two numbers using call by reference
what is the result of cout<>y; and cout<>x; in the above program?
please please do solve these questions. i need them by tomorrow if possible.
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why we use the 1000 as a limit in this problem.
and if we use this expression(i<= (x||y) on the place of 1000 is true ora noot